Explain the following SQL query: SELECT customer_name, COUNT(*) FROM customerTable WHERE CITY_Name LIKE '%Pu%'

The query attempts to retrieve each customer’s name along with the number of rows that match the condition where the city name contains the substring 'Pu'. It uses the COUNT(*) aggregate function to count rows. However, because the SELECT clause includes customer_name without a GROUP BY clause, most SQL engines will raise an error unless customer_name is functionally dependent on the primary key or the query is run in a mode that allows non-aggregated columns. In a standard ANSI‑SQL context, you would need to add GROUP BY customer_name to group the counts per customer. The LIKE '%Pu%' predicate performs a case‑sensitive pattern match, returning rows where the CITY_Name column contains the letters 'Pu' anywhere in the string. If the database is case‑insensitive, it will match 'Pu', 'pu', 'PUL', etc. The result set would have two columns: customer_name and the count of matching rows for that customer.