Write an SQL query to select the top 10 users by order.

Assuming you have an orders table with a user_id column, you can count the number of orders per user and then order by that count in descending order, limiting the result to 10 rows:

SELECT user_id, COUNT(*) AS order_count

FROM orders

GROUP BY user_id

ORDER BY order_count DESC

LIMIT 10;

This query aggregates orders per user, orders the aggregates by the count, and returns the top 10 users. If you need the most recent orders instead of total counts, you could replace COUNT(*) with a subquery that selects the latest order date per user and then order by that date.